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homework_sol_5_f11

# homework_sol_5_f11 - ME 461 — Mechanical Vibrations...

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Unformatted text preview: ME 461 — Mechanical Vibrations Homework #5 Due Friday, October 7, 2010 Reading Sections 3.1—3.3 Homework Problems 3.1, 3.3 a) & b), 3.8, 3.19 (3.14 — 4th), and 3.24 (3.19 ~ 4”) Answers 3.1) a) 0.0125111, b) 0.015m, and C) 0.0185m 3.3) a) x(t) = —0.0333cos(20t) +0.1333cos(10t) b) X(t) = ~0.1333cos(20t) +0.5 sin(20t) + 0.1333cos(10t) 3.8) m = 9.12 kg 3.19) x(t) =2.52651n(8t) 3.24) 9350) = (—8.572X10'4)sin(104.720 (rad) M6 «6/ ./ Mméwa/é/a # 5‘ F” #4 Q /J ((24000 HIM 5‘ W: %%;;= 3.0948 :43 TX He): go» (.03 (wt) PM 4): Zach?» 37.969 NUS 00:5," X c/W =“0.0185'0 m ' (23.01“! i X3 0.0!83'7"; NOTE: N66M’NE sum 15 EXPECTED 3504155 0.) > a) 2:; £55;me /5 A90" our of [3mg n “(m meow/6 ﬁ/MJION {[email protected] K= 9000 MM M=10¥g Hey: woo co: lot (w) “ ﬂowmbllm .............................................................................. u 0 I m :2 "' 0 l 333 m X0- £2. ____ I—(oo u zany-17' 0'1 M - Li 2" ' 000 LW~ -* [01-3 (0 NM? 0.0333 m 0 En. _ ,Jggmw = , Xowtrwt’ O Mﬁloao): O M K. /omls : OHS-m M: M (Jr: Zara‘s ‘ ‘ N6): ~a/333 (as[20t)+0-55(9(20t’) +0. \333 Cacao t)\ i] / £4:qu “\m U=(55stc{2'w (“A/cf) '4 ﬂew 109 as 3mm: W = 3H“, Nous m X 2’20 mm r M 9(- MAGNWDE moves BE’iUEQU +A~0 ~ _ REacome MY 36 M 0F PMSE, So 5:” mean Eon! 17> 0&- coeear VALUE. lv/i’L—J— z» 53: — I, 2. an X \$9.020 m ’/"(M ‘F + may)“: IS Iwwrher ’F "' THEM wnzzoﬁw mug Po 1: (0 95;- = (“V = [00 w" 5‘ EXAD’HNE MMHMENF Pour? 0F SPBVUG '(7) Gem/MO AND UHEQE FUELS ls Mona) UE'TZ'T ccossm’, ‘X‘ FfZOM EXAMLE Pmtﬁm 2.8 ( Rag), we NOTE -me _______________ ‘‘‘‘ H. 1‘ ( FM”,W6:AM.MWM.W~»W«W.» ow 86 W Foe 8'2” AopzA/é V30F (11' mass Tb THE MM (Mas, me; = mm “P SLmSP ‘ Zdlb + 'Sm/z ma” 009/70 WWW ﬂmw éom : rm; >2 + /<;< = ﬁe) , 4/00 ugh»: : ‘ [5‘2 Mn ' J}, W“ "78,928 mi 1 I X , Fe 2 (m now—wa .. kw L/OO Ugh" “(0.0647olb'szilh')(5 malls); Shoo é-v a: (Dram h 57‘ z b = 0.5 M w'lotf'3§s new) ( 'S‘e-Mﬂe [m 9:—@§L~ 52(19): 95w wt l- 5:9.)1 14M “M“WWWW"’WWM"‘”":“""“Fég” .. w. V A 7 W , ﬂ _ K? K‘Qz+kt\91 ' H’ﬂ‘YOvZSM)‘ +[SDOO N‘M)(0-§M)T' 69“ = O. 32 ma 1 m *2“ (sum/(“W good/@1653) wry: RIMS Q: 0.32% / ,. (lat/.72. 2 574126 = - 8.57%Mo‘" ma 95,55)”: “8.5716 M)"; 5m @4572: CW” ...
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