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Unformatted text preview: (m) x(t) = 0.4959 e2t cos(19.90t+1.438) + x ss (t) 3.30) One possible solution: k = 6675 lb/IN, c =5.366 lbs/IN 3.43a) 0.2588 3.48) x ss (t) =0.00114sin(20t + 0.2291) 3.49) b) has reduced steady state response...
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This note was uploaded on 01/29/2012 for the course ME 444 taught by Professor Staff during the Fall '08 term at Michigan State University.
 Fall '08
 STAFF

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