homework10_f11 - 10-4 F sin t, = 1.0 rad x 2 (t) = 17.3165...

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ME 461 – Mechanical Vibrations Homework #10 Due Friday, November 11, 2011 Reading Sections 5.6 and Section 9.11 Homework Problems 5.56 (5.48-Ed4), 5.57 (5.49-Ed4), 5.60 (5.52-Ed4), 5.62 (5.54-Ed4), 9.63 (9.51Ed4), 9.64 (9.52- Ed4), 9.66 (9.54-Ed4), 9.72 (9.60-Ed4) 5.56) x 1 (t) = 0.0040004cos ω t – 0.000001936 sin ω t, ω = 125.66 rad/s x 2 (t) = 0.00009221cos ω t – 0.00002948 sin ω t 5.57) g G ± ² ³ ´ ³ 5.60) x 1 (t) = 17. 2915 × 10 -4 F 0 cos ω t + 6.9444
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Unformatted text preview: 10-4 F sin t, = 1.0 rad x 2 (t) = 17.3165 10-4 F cos t + 6.9684 10-4 F sin t 5.62) x 1 (t) = -0.06469 sin t, = rad/s x 2 (t) = -0.36439 sin t 9.63) m 2 = 40.5 kg, k 2 = 637.97 kN/m 9.64) = 0.3403, m 2 = 102.09 kg, k 2 = 2.519 10 6 N/m, X 2 = -0.1959 mm 9.66) a) m 2 = 489.38 lb, b) 1 = 49.182 rad/s, 2 = 80.265 rad/s 9.72) X 2 = -0.004 m...
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This note was uploaded on 01/29/2012 for the course ME 444 taught by Professor Staff during the Fall '08 term at Michigan State University.

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