Problems and Questions for Chapter 2 Material

Problems and Questions for Chapter 2 Material - Normal...

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Name: Hellums, Jessica UTEID: JSH575 T/TH 2:30 Finklea Problems and Questions for Chapter 2 Material C14: a. 1 b. ½ c. ¾ x ¾ x ¾ = 42.2% C27: Attached A1: Su is dominant to su because the product that this gene encodes is probably an enzyme necessary for the anabolic pathway that polymerizes glucose into starch. Sweet corn is su so it lacks the enzyme necessary to make the glucose into starch and as a result, has more sugar than starch. Field corn has the genotype SuSu or Susu and therefore has all of the necessary enzyme for the anabolic pathway to get starch, or it has half the normal amount of enzyme to get starch from glucose. Either way, the enzyme is available to build starch so even with half the enzyme, it can still get to a point where it has more starch than sugar. E10: W: wing type ww: curved W_: normal B: body type B_: gray bb: ebony a. P: wwBB x WWbb Curved wings, gray body x normal wings ebony body F 1 : WwBb
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Unformatted text preview: Normal wings, gray body F 2 : Bb wwBb ww bb wwbb Ww Bb WwBb bb Wwbb b. wwB_ (curved wings, gray body) wwbb (curved wings, ebony body) W_B_ (gray body, normal wings) W_bb (normal wings, ebony body) c. Name: Hellums, Jessica UTEID: JSH575 T/TH 2:30 Finklea Problems and Questions for Chapter 2 Material see attached E15: Hypothesis: herbicide resistance is dominant and disease sensitivity is dominant, and the genes are unlinked, or independent. F 2 : disease sensitive disease resistant herbicide resistant herbicide sensitive (3/4 x 3/4) = 9/16 disease sensitive, herbicide resistant (3/4 x ) = 3/16 disease sensitive herbicide sensitive (1/4 x 3/4) = 3/16 disease resistant herbicide resistant (1/4 x ) = disease resistant herbicide sensitive See attached for chi squared test E16: See attached paper...
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This homework help was uploaded on 04/07/2008 for the course BIO 325 taught by Professor Saxena during the Spring '08 term at University of Texas at Austin.

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