This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: [2 , 3]. Note that this was a pretty arbitrary choice, the main goal was to make it easy to check the conditions of the xed point theorem. 4. For part (b) try something similar to the previous problem. 5. Just use the formula for Newtons method. Note that for f ( x ) =-x 3-cos x we have that f ( x ) =-3 x 2 + sin x so that f (0) = 0 so it will not be possible to carry out the Newton iteration if 0 is chosen as the initial point because carrying out the rst step of the iteration requires dividing by f (0) = 0. Geometrically Newtons method calculates the zero of the tangent line at the initial point. If f ( p ) = 0 then the tangent line at p is horizontal and does not have a zero. 1 6. See Burden and Faires for some pseudo - code for these methods. 2...
View Full Document