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Unformatted text preview: Calculations: Initial concentration (NCS) 1 solution #4: M 2 = = Initial concentration of Fe 3+ solution #4: Equilibrium concentration [Fe(NCS)] 2+ = 0.231= 4720.9x + 0.0008 x= 4.88x105 Equilibrium concentration Fe 3+ (M) = 3.6 x 104 – 4.88x105 = 3.1 x 104 Equilibrium concentration (NCS) 1 (M) = 8.9 x 104 – 4.88 x 105 = 8.4 x 104 K c = Initial concentration (NCS) 1 solution #5: M 2 = = Initial concentration of Fe 3+ solution #5: Equilibrium concentration [Fe(NCS)] 2+ = 0.247=4720.9x + 0.0008 x= 5.22x105 Equilibrium concentration Fe 3+ (M)= 3.6x104 – 5.22x105 = 3.0 x 104 Equilibrium concentration (NCS) 1 (M) = 0.0011 – 5.22x 105 = 0.0010 K c = Initial concentration (NCS) 1 solution #6: M 2 = = Initial concentration of Fe 3+ solution #6: Equilibrium concentration [Fe(NCS)] 2+ = 0.194 = 4720.9x + 0.0008 x= 4.09 x105 Equilibrium concentration Fe 3+ (M)= x 104 – 4.09 x105 = 6.7 x 104 Equilibrium concentration (NCS) 1 (M) = x 104 – 4.09 x 105 = 3.2 x 104 K c = Percent error:...
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This note was uploaded on 01/30/2012 for the course CHEMISTRY 212 taught by Professor Ha during the Spring '11 term at George Mason.
 Spring '11
 Ha
 Equilibrium

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