eq experiment - Calculations: Initial concentration (NCS)...

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Unformatted text preview: Calculations: Initial concentration (NCS) 1- solution #4: M 2 = = Initial concentration of Fe 3+ solution #4: Equilibrium concentration [Fe(NCS)] 2+ = 0.231= 4720.9x + 0.0008 x= 4.88x10-5 Equilibrium concentration Fe 3+ (M) = 3.6 x 10-4 – 4.88x10-5 = 3.1 x 10-4 Equilibrium concentration (NCS) 1- (M) = 8.9 x 10-4 – 4.88 x 10-5 = 8.4 x 10-4 K c = Initial concentration (NCS) 1- solution #5: M 2 = = Initial concentration of Fe 3+ solution #5: Equilibrium concentration [Fe(NCS)] 2+ = 0.247=4720.9x + 0.0008 x= 5.22x10-5 Equilibrium concentration Fe 3+ (M)= 3.6x10-4 – 5.22x10-5 = 3.0 x 10-4 Equilibrium concentration (NCS) 1- (M) = 0.0011 – 5.22x 10-5 = 0.0010 K c = Initial concentration (NCS) 1- solution #6: M 2 = = Initial concentration of Fe 3+ solution #6: Equilibrium concentration [Fe(NCS)] 2+ = 0.194 = 4720.9x + 0.0008 x= 4.09 x10-5 Equilibrium concentration Fe 3+ (M)= x 10-4 – 4.09 x10-5 = 6.7 x 10-4 Equilibrium concentration (NCS) 1- (M) = x 10-4 – 4.09 x 10-5 = 3.2 x 10-4 K c = Percent error:...
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This note was uploaded on 01/30/2012 for the course CHEMISTRY 212 taught by Professor Ha during the Spring '11 term at George Mason.

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eq experiment - Calculations: Initial concentration (NCS)...

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