eq experiment - Calculations Initial concentration(NCS)1...

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Calculations: Initial concentration (NCS) 1- solution #4: M 2 = = Initial concentration of Fe 3+ solution #4: Equilibrium concentration [Fe(NCS)] 2+ = 0.231= 4720.9x + 0.0008 x= 4.88x10 -5 Equilibrium concentration Fe 3+ (M) = 3.6 x 10 -4 – 4.88x10 -5 = 3.1 x 10 -4 Equilibrium concentration (NCS) 1- (M) = 8.9 x 10 -4 – 4.88 x 10 -5 = 8.4 x 10 -4 K c = Initial concentration (NCS) 1- solution #5: M 2 = = Initial concentration of Fe 3+ solution #5: Equilibrium concentration [Fe(NCS)] 2+ = 0.247=4720.9x + 0.0008 x= 5.22x10 -5 Equilibrium concentration Fe 3+ (M)= 3.6x10 -4 – 5.22x10 -5 = 3.0 x 10 -4 Equilibrium concentration (NCS) 1- (M) = 0.0011 – 5.22x 10 -5 = 0.0010 K c = Initial concentration (NCS) 1- solution #6: M 2 = = Initial concentration of Fe 3+ solution #6: Equilibrium concentration [Fe(NCS)] 2+ = 0.194 = 4720.9x + 0.0008 x= 4.09 x10 -5 Equilibrium concentration Fe 3+ (M)= x 10 -4 – 4.09 x10 -5 = 6.7 x 10 -4 Equilibrium concentration (NCS) 1- (M) = x 10 -4 – 4.09 x 10 -5 = 3.2 x 10 -4 K c =
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Percent error: % Concentration of Fe(NCS) vers Absorbance in nm Concentration % Transmittance (%T) A = -log(%T/100) 0.00001 100 0.000 0.00002 81.4 0.0894 0.00003 70.6 0.151 0.00004 64.0 0.194 0.00005 58.8 0.231 Table 1 Figure Conclusion:
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