{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

W11Physics1CLec14A

# W11Physics1CLec14A - Physics 1C Lecture 14A Monday Quiz...

This preview shows pages 1–6. Sign up to view the full content.

Physics 1C Lecture 14A Monday Quiz Topics: Mass on a spring Mass on a string = simple pendulum Equation for simple harmonic motion Energy in oscillations Transverse & longitudinal waves Wave equation Wave interference Doppler Effect I.e. this inlcudes topics covered in class up to and including last wednesday

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Standing Waves in Strings For a string fixed at both ends, the longest standing wave we can achieve is: The frequency for this standing wave is known as the fundamental frequency or the first harmonic . The length, L , of the string is equal to one-half the wavelength. We label standing waves by the number of anti-nodes, so this wave is n = 1 .
Standing Waves in Strings The next longest wavelength that we can achieve on this string is n = 2 . Here, L = λ The next longest wavelength that we can achieve on this string is n = 3 . Here, L = (3/2) λ

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Standing Waves in Strings For the n th harmonic: L = n 2 l n =1, 2, 3, 4... λ = 2 n L Recall that: f n = v l = nv 2 L v = l f So in general the frequency will be: The different frequencies are known as harmonics for standing waves. Just choose n =5 if you want a standing wave with 5 anti-nodes.
Standing Waves: Math Model Assume two waves with the same amplitude, frequency and wavelength, traveling in opposite directions in a medium: y 1 = A sin ( kx ϖ t ) and y 2 = A sin ( kx + ϖ t )

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern