Lecture Notes 1.3

Lecture Notes 1.3 - More with FBDs Breaking up joints 1 Segmented Body Analysis 2 Individual FBDs 3 FBD#2 4 Equations and unknowns Nine 6 9 5

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1 More with FBD’s: Breaking up joints
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2 Segmented Body Analysis
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3 Individual FBD’s
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4 FBD #2
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5 Equations and unknowns Nine 6 9!!!
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6 Newton’s 3 rd law For every action there is an equal and opposite reaction! Biceps force on upper arm = and opp to biceps force on lower arm. Etc….
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7 Matrix α sin 0 0 0 cos 1 0 0 0 0 sin 0 1 0 0 0 sin sin sin 1 cos 1 0 0 1 0 sin 0 1 0 0 1 r r r r
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8 Matrix Could also introduce the constraints as actual equations (there would be 3: 1) F bicep upper=F bicep lower 2) F xelbow upper = F xelbow lower 3) F yelbow upper = F yelbow lower Why only one equation for biceps but two for elbow?
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9 CONSTRAINTS Recall example from last lecture – We called the “shoulder” joint the joint + muscles – Why did we need to do this?
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10 CONSTRAINTS Just as when I stomp on the floor, the floor “stomps” back up on me (the reaction), the weight of the upper and lower arms and apple produce torque on the shoulder, and their must be a reaction moment at the shoulder = and opp to these forces to maintain SEQ. How does the shoulder do this?
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CONSTRAINTS Q: How does shoulder do this? A: With muscles Q: What would happen if we removed the muscles that support the shoulder? A: It would rotate down. Q: Why?
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This note was uploaded on 01/30/2012 for the course 125 208 taught by Professor Shreiber during the Spring '08 term at Rutgers.

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Lecture Notes 1.3 - More with FBDs Breaking up joints 1 Segmented Body Analysis 2 Individual FBDs 3 FBD#2 4 Equations and unknowns Nine 6 9 5

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