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Unformatted text preview: arriaga (yga77) – HW06 – quy – (50970) 1 This print-out should have 25 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A sigma bond 1. may exist alone or in conjunction with a pi bond. 2. is always polar. 3. is composed of non-bonding orbitals. 4. always exists in conjunction with a pi bond. 5. stems from sp hybridization of orbitals. 002 10.0 points In a new compound, it is found that the cen- tral carbon atom is sp 2 hybridized. This implies that 1. carbon has four lone pairs of electrons. 2. carbon has four sigma bonds. 3. carbon is also involved in a pi bond. 4. carbon has a tetrahedral electronic geom- etry. 5. carbon has four regions of high electron density. 003 10.0 points In the molecule, C 2 H 4 , what are the atomic orbitals that participate in forming the sigma bond between the C and H atoms? 1. H: 1 s and C: sp 2. H: 1 s and C: 2 p 3. H: 2 p and C: sp 3 4. H: 1 s and C: sp 2 5. H: sp 2 and C: sp 2 004 (part 1 of 4) 10.0 points Draw the Lewis structure for the following hydrocarbon molecule. The carbons are num- bered one to four starting with the far left carbon as one. CH 2 CCHCH 3 What is the molecular shape of carbon 3? 1. trigonal planar 2. bipyramidal 3. trigonal pyramidal 4. tetrahedral 5. square planar 6. angular 7. linear 005 (part 2 of 4) 10.0 points What is the hybridization of carbon 4?What is the hybridization of carbon 4?...
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This note was uploaded on 01/30/2012 for the course CHEM 301 taught by Professor Wandelt during the Spring '08 term at University of Texas at Austin.
- Spring '08