1stmidterm - a) If the lower end of the chute is a vertical...

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Physics 1A January 27th 2010 Midterm # 1 Name: D i s c u s s i o n S e c t i o n : 1) A car starts to turn on a curve of radius R with constant tangential acceleration a . At the beginning of the turn the initial velocity of the car is v 0 . Calculate a) the time at which the centripetal acceleration is equal in magnitude to the tangential acceleration and b) the distance traveled by the car from the moment when it started to turn. (Numerical data: R=9m, a =1m/s 2 , v 0 =1m/s).
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2) In a shipping company distribution center, an open cart is rolling to the left at a speed of v (see the figure). You can ignore friction between the cart and the floor. A package slides down a chute that is inclined at an angle θ = 30 degrees from the horizontal and leaves the end of the chute with a speed of v0 = 3 m/s. At that instant the cart is at a horizontal distance D = 10 m away from the position immediately below the lower end of the chute.
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Unformatted text preview: a) If the lower end of the chute is a vertical distance of h = 4.00 m above the ground, what has to be the velocity of the cart such that the package lands on the cart? (Hint: calculate first t*, the time it takes for the package to land. Express your answers in terms of t*). b) What is the speed of the package just before it lands in the cart? = 30 deg v0= 3 m/s D= 10 m H = 3 m 3) Two blocks are connected by a cord passing over a small frictionless pulley rest on frictionless planes at angles 1 = 30 degrees and 2 = 45 degrees respectively with the horizontal (see Figure). a) Draw free body diagrams for each of the block. b) If m 1 =10 kg, what has to be m 2 for the system to be in equilibrium? c) If I now reduce m 2 to be half of the equilibrium value, what is the acceleration of the system? m 1 m 2 45...
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This note was uploaded on 01/31/2012 for the course PHYSICS 1a taught by Professor Corbin during the Winter '11 term at UC Davis.

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1stmidterm - a) If the lower end of the chute is a vertical...

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