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Unformatted text preview: ( 29 ( 29 ( 29 3 2 1 8 15 5 50 C KG s G s s s K s K + = → + + + + = Substituting s = jω into the closed–loop characteristic equation and rearranging 2 2 50 8 15 5 K K j ϖ + += Setting the real and imaginary parts equal to zero and solving simultaneously, K = 12. Therefore, the closed–loop system is stable for 0 < K < 12. The closed–loop system is underdamped for all K . The 2% settling time decreases as K increases and approaches ∞ as K approaches 12. Since the closed–loop system is marginally stable for K = 12, the steady–state error cannot be calculated. The Root Locus Diagram and simulation plots are given below. 5 2 4 6 time (s) r y 50.2 0.2 time (s) e(t) 51 1 2 time (s) u(t)15105 550 50 2...
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This note was uploaded on 02/01/2012 for the course MECH ENG 279 taught by Professor Landers during the Spring '11 term at Missouri S&T.
 Spring '11
 LANDERS

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