stability4

# stability4 - 29 29 2 1 3 2 K s s K The Routh table is 2 1 1...

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Stability Q UESTION 4 For the system shown in Figure 4 with ( 29 ( 29 ( 29 ( 29 2 1 1 2 K s G s s s + = + + , create the Routh table and determine for what range of K the closed–loop system is stable. Figure 4 The closed–loop transfer function is ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 2 2 1 1 1 3 2 K s G s T s G s K s s K + = = + + + + + . The closed– loop characteristic polynomial is
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Unformatted text preview: ( 29 ( 29 2 1 3 2 K s s K + + + + . The Routh table is 2 1 1 2 3 2 s K K s s K + + + . There will only be a sign change in the first column if K < –1 or K < –2. Therefore, the closed– loop system will be stable for K > –1....
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