steadystateerror11

steadystateerror11 - and, therefore, the steadystate error...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Steady State Error Q UESTION 11 For the system shown in Figure 11 with ( 29 ( 29 ( 29 ( 29 ( 29 3 2 5 1 5 3 8 12 s s F s s s s s + + = + + + , calculate e (∞) for the input r ( t ) = 12 t 3 . + - R(s) F(s) Y(s) E(s) Figure 11 The closed–loop transfer function is ( 29 ( 29 ( 29 ( 29 ( 29 2 6 5 4 3 2 5 6 5 1 11 36 36 5 30 25 s s Y s F s R s F s s s s s s s + + = = + + + + + + + . From the Routh Table below, it can be seen that the closed–loop system has two unstable poles
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: and, therefore, the steadystate error cannot be calculated. 6 5 4 3 2 1 1 36 5 25 11 36 30 32.73 2.273 25 35.24 21.60 17.79 25 73.69 25 s s s s s s s-...
View Full Document

Ask a homework question - tutors are online