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Unformatted text preview: D20) = 0 This implies 4 C + 8 D = 36 8 C + 26 D = 112 . 1 A T Ax = A t b is given by 4 8 8 26 C D = 36 112 . 6. Problem Set 4.5, p. 217, # 12 b = ( b 1 , . . . , b m ) and a = (1 , . . . , 1). Observe that there is a change in notation and b, a denote a row vectors. Thus b T , a T will denote column vectors. (a) a T a x = a T implies that m x = m i =1 b i and x = 1 m m i =1 b i . (b) e = ba x = ( b 1 x, . . . , b m x ). Then k e k 2 2 = m i =1 ( b i x ) 2 and k e k 2 = { m i =1 ( b i x ) 2 } 1 / 2 . (c) b = (1 , 2 , 6), a = (1 , 1 , 1), b = 3 and p = (3 , 3 , 3). Then for e = bp = (2 ,1 , 3) we have pe T = 0 and P = a T a k a T k 2 2 = 1 3 1 1 1 1 1 1 1 1 1 . 2...
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This note was uploaded on 01/31/2012 for the course COMS 3251 taught by Professor Anargyrospapageorgiou during the Fall '11 term at Columbia.
 Fall '11
 AnargyrosPapageorgiou

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