Standard Normal Probablitys exam

Standard Normal Probablitys exam - 1. A large normally...

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1. A large normally distributed population has a mean of 150 and a std. dev. Of 12 a. Find the probability that a random selected score is between 150 and 157. b. If a sample of size n = 100 is randomly selected, find the probability that the sample mean will be between 150 and 157. a. Z value= So z value for 150=z1=150-150/12=0 And z value for 157=z2=157-150/12=0.58 So we have to find p(z1<z<z2)=p(0<z<0.58)=0.7190 b. The normal dist. Is itself a case of increasing no. of N. As N increases in binomial dist. It changes to normal dist. The only effect of increasing the sample size is that the sample will stick to each other with a less distance and follow the same normal dist. The samples will be more closely to each other. But no effect will be on prob. 2. At the α =0.05 significance level, test the claim that the proportion of fraudulent credit card applicants is more than 0.23. A sample of n=1200 reveals that 26.3% of them are fraudulent. Z Test of Hypothesis for the
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This note was uploaded on 01/31/2012 for the course QM 2113 taught by Professor Kent during the Fall '11 term at ASU.

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Standard Normal Probablitys exam - 1. A large normally...

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