EE 230 HW 12 Solutions Spring 2010

EE 230 HW 12 Solutions Spring 2010 - For example, if the...

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% % % % % % % hw 12 matlab code of problem 7 % % % % % % n=12; VREF=1; VLSB=VREF/2^n; Ts=100*10^(-6); T=0:Ts:Ts*(200-1); % origional signal S=0.5+0.5*sin(1000.*T); % Interpreted voltage Vout=floor((0.5+0.5*sin(1000.*T))./VLSB).*VLSB; % Boolean output Boolean=dec2bin(floor((0.5+0.5*sin(1000.*T))./VLSB)); plot(T,S,'-r') hold on plot(T,Vout,'-*') legend('Origional signal','Interpreted voltage') 0 0.002 0.004 0.006 0.008 0.01 0.012 0.014 0.016 0.018 0.02 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 Problem 7 Origional signal Interpreted voltage
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Problem 8 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 x 10 -3 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 Origional signal Part b Part c Part d (a) See figure above (b) We can not reconstruct the original signal from the sampling results without any prior information.
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Unformatted text preview: For example, if the input signal is a sine wave having twice the frequency or a triangular waveform having same time period. Even if we know the sampling frequency is larger than or equal to the input frequency, we still can not tell whether the input is a sine wave (We would not be able to find the amplitude.) or a zero input (no input). (c) If we know the sampling frequency is larger than or equal to the input frequency, we can recover the input signal. (d) It is impossible to reconstruct the signal as the sampling frequency is not large enough. (e) See comments above....
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EE 230 HW 12 Solutions Spring 2010 - For example, if the...

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