EE 230 Lecture 14 Spring 2010

# EE 230 Lecture 14 Spring 2010 - EE 230 Lecture 14 Basic...

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EE 230 Lecture 14 Basic Feedback Configurations Second-Order Filters Difference Amplifiers Impedance Converters

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Quiz 10 a) Determine the transfer function T(s)=V OUT (s)/V IN (s) for the circuit shown b) Is the circuit stable? Assume the op amps are ideal and all resistors are 1 and all capacitors are 1F
And the number is ? 1 3 8 4 6 7 5 2 9 ?

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Quiz 10 a) Determine the transfer function T(s)=V OUT (s)/V IN (s) for the circuit shown b) Is the circuit stable? Solution:
Quiz 10 a) Determine the transfer function T(s)=V OUT (s)/V IN (s) for the circuit shown b) Is the circuit stable? Solution:

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Quiz 10 a) Determine the transfer function T(s)=V OUT (s)/V IN (s) for the circuit shown b) Is the circuit stable? Solution: s V OUT 2 OUT s V s V IN
Quiz 10 a) Determine the transfer function T(s)=V OUT (s)/V IN (s) for the circuit shown b) Is the circuit stable? Solution: s V OUT 2 OUT s V s V IN OUT OUT IN OUT 2 VV V V = -- -- - ss s

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Quiz 10 a) Determine the transfer function T(s)=V OUT (s)/V IN (s) for the circuit shown b) Is the circuit stable? Solution: OUT OUT IN OUT 2 VV V V = -- -- - ss s 2 OUT OUT OUT IN sV - sV + V = sV ( ) 2 OUT IN V s -s+1 = sV () OUT 2 IN V s Ts Vs - s 1 == +
Quiz 10 a) Determine the transfer function T(s)=V OUT (s)/V IN (s) for the circuit shown b) Is the circuit stable? Solution: () OUT 2 IN V s Ts = = Vs - s + 1 Poles at 1+j 3 s = 2 1-j 3 s = 2

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Quiz 10 a) Determine the transfer function T(s)=V OUT (s)/V IN (s) for the circuit shown b) Is the circuit stable? Solution: () OUT 2 IN V s Ts Vs - s 1 == + Poles at 1+j 3 s = 2 1-j 3 s = 2 RHP RHP
Quiz 10 a) Determine the transfer function T(s)=V OUT (s)/V IN (s) for the circuit shown b) Is the circuit stable? Solution: () OUT 2 IN V s Ts = = Vs - s + 1 Poles at 1+j 3 s = 2 1-j 3 s = 2 LHP RHP Since there is one RHP pole, the circuit is unstable !

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Inverting Integrator () 1 Ts sRC =− 1 Tj ω j ω RC 1 ω ω RC = 90 ω o ∠= Unity gain frequency is 0 1 ω RC = Review from Last Time
Noninverting Integrator () () 0 OUT IN IN 1 VV V 0 RC t d ττ =+ Obtained from inverting integrator by preceding or following with inverter Also widely used Same issues affect noninverting integrator Requires more components Review from Last Time

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First-order lowpass filter with a dc gain of R 2 /R 1 () 2 12 R1 Ts + s C R ⎛⎞ =− ⎜⎟ ⎝⎠ ( ) Tj ω 2 1 RC 2 1 R R R 2 controls the pole (and also the dc gain) R 1 controls the dc gain (and not the pole) Review from Last Time
OUT IN OUT IN V sRC = V1 + s R C This is a first-order high-pass amplifier (or filter) But this looks like a useful circuit!

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## This note was uploaded on 02/01/2012 for the course EE 230 taught by Professor Mina during the Fall '08 term at Iowa State.

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EE 230 Lecture 14 Spring 2010 - EE 230 Lecture 14 Basic...

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