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Unformatted text preview: PT? What is the safe vehicle speed? Solution: The stationing of PC is 000 . 45 7 000 . 155 ) 000 . 200 7 ( + = − + = PC The stationing of PT is 898 . 338 7 898 . 293 000 . 45 7 180 45 ) 2 / 45 tan( 155 000 . 45 7 180 ) tan( 180 2 + = + + = ° × ° × ° + + = ° × Δ × + = ° × Δ + = Δ π T PC R PC PT The radius of curvature of the innermost lane is m R R v 70 . 369 5 . 4 20 . 374 ) 2 / 3 3 ( = − = + − = Therefore, hr km s m V e f gR V e f g V R s v s v / 39 . 89 / 83 . 24 ) 09 . 08 . ( 70 . 369 81 . 9 ) ( ) ( 2 = = + × × = + = ⇒ + =...
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This note was uploaded on 02/01/2012 for the course CIVL 262 taught by Professor Lee during the Spring '09 term at HKUST.
 Spring '09
 Lee
 Transportation Engineering

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