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Cong Thuc Dao Ham - Céng thl'Ic Dao He‘lm Cfia Mét S63...

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Unformatted text preview: Céng thl'Ic Dao He‘lm Cfia Mét S63 He‘lm SO’ Cép ’ (CT = a (c 121 hang s6) {£7 = m“ n 63 7 ’ = I 1 (er) a (hx}’=—: xii-D , x 7 (Finis)I = max [uyzmgjcjlI = —5in x 1 1 t I = r 1 t ‘1'! = _ (gx) coslx hoéc {EX} = 53‘: x hoéc (CD gx_ sin 2;: hoéc l l t I = ‘7 J‘ 2 t ‘1: = _ I: 3111:} cos 3): hoéc {tan I}; = 5552 I , trong {mtg 1:} = — 5°53“: 3'3 hoéc (CD x_ 55112 1: d6 SEC}.- = l/tCDSI .[1*] hOEIC {501x}! : — CDSflCEI trong do’ 7 cosecx= lfsinx. 7 (513ch = secxtanx (com I}! = — cosecxcotx l l (attain 31:}I = (arenas 3c}r = — Vl—xlhoéc Vl—xlhoéc r l r l - —1 —1 5m x = cos x = — ,( ) VII—x3, l ,( } VII—Jr:2 l 7 r —1 I J‘ —1 I Ct = t = t = t = 7 (at gx} 1 +411:2 hoéc ( g I) 1 +41:2 (amen gx} l +_1c2 hoéc (CO g x) l +_:c2 (sink 11:}1 = coshx [2*] (:43le 1:}! = ainhx {tank I}! = 555911135 , trong d6 sechx= 1/(cosh {until I}! = — 0055311135: I ‘t 0 ,trong d6 7x). 7 (SiacllnjflI = — 56::thth 7cosech x = 1/(sinh x). 7 (cased: x}! = — cosech xcofh x, x at Q [1*] Khéc vc'ri he théng Chfiu éu, bén Hoa Ky hay mét s6 nuéc thuéc Béc My ho dimg thém ky' hiéu sec x = 1/(cos X), cosec x = 1/(sin x). Ngoéi ra, céch Viét cho mét 36 him so cép cfing cé Sl_l' khéc biét trong k}? hiéu: tan x : tg x cot x = cotg x arctan x = arctg x arccot x = arccotg x [2*] Djnh nghia ham hyperbolic z_ —x 1+ —1 shahx=€ 29 ficoshx=e 2g sinhx tan]: = x coshx 77th77coshx 1 sec—h = x £05113: sec]: 1 to X: sinhx T1‘I djnhnghTa hz‘tmsinhxvé coshx,tatimduqc: coshxl—sinhxl=l sinhlx=25inhxmshx m5h2x= cosh2x+sinh2x=2coshzx— 1= l+25inh2x Copyright 2005—2011 http://toantructuyen.seriesmathstudy.com. All rights reserved. Contact us. Ghi r6 nguén "http://toantructuyen.seriesmathstudy.com" khi ban déng lai théng tin ta website nay. ...
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