EEE4306_QUIZ_1_2011_Solution_Summer

EEE4306_QUIZ_1_2011_Solution_Summer - EEE 4306 QUIZ 1, 100...

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Unformatted text preview: EEE 4306 QUIZ 1, 100 Points Name: 7 [WW ‘L’ 60 Minutes. Open Note, Open Book, 5/23/11 UFID . Circuit Element Values, Vsumy = 12V M1: Rm = 50 K9, Rm = 200 KS2, R02 = 100 KQ, RD= 5 K9, M2: R63 = 100 K9, R54 = 100 KS2, RL =1 KS2, Q11Rx=2KQ, R131: 30 KQ, R32 = 15 K9, RE] = 100 Q, RC: 5 Kg, BJT parameters: B = 120, VA = 00V, base-emitter VBEON :— 0.7V, Thermal voltage, Vt = 0.025V, MOSFET Parameters, VT = 1 V, k = 4mA/V2 == l/2unCox(W/L) , 9» = 0.04 VSUPPLY £3; VX g 12 x/a 9" EB, rflaz :. [Z \// /5kJL I§fm+ 30H)— : l/l/ VSUPPLY ffM A- : 3. Elfin. CM RB) M392 —; 33A (*5 Ega<¢ ’QE VOUT RL V Ti, K6; ‘ /D0i< "LAM I )7” Biasing Calculation: (15 points): Find the numerical values for the circuit elements : l 4, [m A below. V afiwa PickREandRsLRszsothatIE=Im=lmAandID2=4mA. :1 ‘ Vzpcfi/em all—LEV RE: 3, 3 , R51 = :— M. a—e- D; x V V a [00m :év yoa w 71V WEN/ka V65 ,: ' +‘/:I" ~ V+ “WA =Z\/ . n W. Eisenstadt 1 Midband Gain Calculation: (65 points) Assume C1, C2, C3, C4, C3 and CE = 00 for this section of the quiz. These capacitors will short all signals except for DC. Use the values of RE, R5 and R32, from above. Input MOS Section Gain: (5 points out of 65) Write the expression (equation) for the input section gain Vz/Vm in terms of the circuit elements above. Use the small-signal values of V_zflfl\_1; 2=Mfelllfiez w W, VIN RIM ~l— Pad/R61 _— 50kg {—[DO/VJZHZaOk/L Find and report the numerical value of the input section gain. "—2= 0,57 VIN MOS Transistor Stage Gain: (15 points out of 65) Write the expression (equation) for the MOS Input stage gain Vy/Vz in terms of the circuit elements above. Use the small—signal valuesofVX/l; gym“: :v :qmfi/go ~— (RomainQaltailwtfié) Find and report the numerical value of the stage 2 gain. -4m24/V(9I<HZS 2:12!) loom” ’00.” WWW) V2 , _. _}_.—-—-’ .. : ’_ 3’7 ‘ V/V ROW :‘FLib’M’DLO/W’A— Zy/CJL BJT Stage 1 Gain: (20 points out of 65) Write the expression (equation) for the stage 1 section gain Vy/V signal in terms of the circuit elements above. Use the small-signal values of Vy/Vm. Note: R_ = 2K Q. v. z Kallalmrw— (gamma mm Rx+ R9, HEEL” (WAEHXRE, 12/85) Find and report the numerical value of the stage 1 gain. 3m.” 5 HUI (3 k,” mama.) VY ‘ - ' "/11? v 2 2 kn. +30hll lfk/Ll(31:a+12ar?7J§ 1+t/0m4/v ~ Signal ‘er 1 ’/ W. Eisenstadt 2 - ‘ MOS Stage 2 Gain: (20 points out of 65) Write the expression (equation) for the MOS stage 2 gain Vout/Vy in terms of the circuit elements above. Use the small—signal values of Vout/Vy E/ffiliz+_ 9m; 7— z/M/wz/m/t Find and report the numerical value of the stage 2 gain v :1” : /! -~--- (9. a ) l m” "91+ 8mm) Gain Comparison: (5 points out of 60). Which amplifier gain is higher, the BJT-to—MOS (VOUT/VSignal) or the MOS-to-MOS (Vout/VIN) and Why? «I'M {37734-04105 9454/: Ika "/33 x 055‘ 2:70.; Hr M0549,MDS and “2 ~10 WM (937387MA/V X 623 W ETT-rba/st 9am i3 Ltlfilc: VWYOOL WHIP/y W awe abet“ 41 weaving? €WQS' W. Eisenstadt 4 W, 7M)»: 2'7'19 3 [pt/5 Low Frequency Capacitance: (20 points), What values of capacitances Cs and CE would you pick if you wanted to set up separate poles at 25 Hz with each capacitor. Would the overall circuit (0L be closeto 50 Hz if all the other capacitors are set to 10 uF? Why or why not? . l ____L, z / .5 2/7JL I ¢9W EgII/QM’ 2,5’szZ) (MA/V, Z __ __L__._. _ - C3: 2’77'2/5’22'7 _ “3' Range: ZJ‘LF + (“W “W -» C W Kg 1— [3/2 ~ 5' . E 3 (3H CE: :[Objl‘i‘ F2 ‘EQCE 72/ ; fir—fly” :: ’gFJL 1/7—r"‘7/§/‘L2/' 1 0%: car Jar—r : I2 51/5 C AM Zia/Lt l§’="30’=”(’“1r+/2”§'”5)£ 3H: {/61 r * weaving/ext I 4’ fkfl” ’DQMU/wmfilng” : 9/31 w¢>,’/“Jf" : llJr/5 ‘ {It W ( i: A :2 W ZLf/‘Jp‘t SHL” [ak/Zime/UL: wLB g l/ r/S 5 ..—-'~ .. "i A; 'far‘re— 2. fl ng magma” 2W”; 4" j / 7 EJL Lac; 5? M791}, air/5 Bonus High 14 requeney Cutoff: (5 pomts). Assume all the high frequency capagifd s are very smallrlnsertionecapacitor infithebestiplaceinthecircuitrequiring the lowest 7 ~ 77 ~ 7 7 ~ 7 r 7 W W a necessary capacitance (draw it on the circuit schematic) to limit the high frequency V response to 500 KHZ. What is the value of that High Frequency Capacitor? Q, \ h. - 1‘ 377‘)" -—-’ , HF’SW 9M3W in? 2%+Z%2/= g/‘fléfipéil/f = may F Mao/.24 A5 M “ MC@@ 7% g9 5! CH; Wyeth (l“”4> + EL—Fva M‘t Vie/6170425, '— fi , (‘M‘QJ _ pad,le “£32” {by (I a /?(3>4(§k/IS/://oflpf“fl/MWQ/ : /a (fig/€043) 4— 25km. WM, Z: r ‘5 i = 27 (7734. 4/3 L/Zg/S > 53% 52:; g .1. r. ’ __ ’ 2772; ) ZTTGfF—"flaa ) CHF‘ 2.7T,§poklé-Z?.Lflm, W. Eisenstadt 6 :: F ...
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EEE4306_QUIZ_1_2011_Solution_Summer - EEE 4306 QUIZ 1, 100...

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