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Unformatted text preview: =24 in.z t = 4.6 =B(8D4\2 B =4.61(0.333)2 = 41.48 min/in.2 (b) For the bar, assuming that B = 41.48 minfn.2: Y= (0.5X0.5)(6) = 1.5 in.2 A = 2(0.5X0.5) + 4(0.5)(6) = 12.5 in.2 1= (41.48)(1.5112.5\2 = 0.60 min Qo=3'56 A 945 A cooling curve is shown in Figure 9-2|.Determine (a) the pouring temperature, (b) the solidification temperature, (c) the superheat, (d) the cooling ratejust before solidification begins, (e) the total solidification time, (f) the local solidification time' and (g) the probable identity of the metal. (h) If the cooling curve was obtained at the center of the casting sketched in the figure, determine the mold constant, assum' ingthatn=2. Solution: (a) Toou , = 47 soc (b) ?Lr = 32oPc (c) 47" = 475 - 320 = 155oC 475 - 320 (d)4nfu1 = ,rr* =1.0oC/s ( e ) f = 4 7 0 s (f) LST = 470 - 170 = 300 s (g) Cadmium (Cd) (h) r, = 470 = B[38 .4t121.612 B - 4713 s/cmz...
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This note was uploaded on 02/01/2012 for the course MSEG 302 taught by Professor Snively during the Spring '08 term at University of Delaware.
- Spring '08