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Unformatted text preview: Use material properties given below: E1 = 125 Gpa E2 = 10 GPa v12 = 0.25 G12 = 5 GPa SOLUTION This solution is almost exactly the same as homework 6 solution except for: i) T=1kN.m The torque will contribute to Nxy, which needs to be in units of Force/unit length. Nxy=Torque/(circumference*radius) = T/(2*π*r 2 ) Next, find Q, , and in the same way as in homework 6. Since the laminate is symmetric, [B] = 0. Since there is no moment, we don’t need to worry about solving for [D] and [κ] = 0 Then, It follows that To find stress in the material coordinates, ii) The process for this section is the exact same, but the N vector is based on the axial force/unit length… Nx=P/(2*π*r 2 ) iii) This step is simply superposition of the previous two solutions....
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 '10
 PETRINA
 Force, Coordinate system, Composite material, 30mm, 0.25mm, Nxy

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