Experiment 2 Lab

# Experiment 2 Lab - falling object on earth if there is no...

This preview shows pages 1–2. Sign up to view the full content.

Introduction: Finding the acceleration of a falling object and comparing to 9.8m/s^2. 1) If we time the fall by hand, the measurements will not be as precise as an instrument designed for this measurement. Our reaction time is not good enough to compare to measuring devices, and reaction time varies between people. 2) Slope is gravity x2. The acceleration due to gravity on the 16mm ball is 8.724m/s^2 and dividing it by g shows there is 11% error and on the 19mm ball is 8.646m/s^2 giving 12% error. 3) The percent error was very small, but it is still different from what was measured and the accepted value air resistance is one possible factor.air resistance becomes greater as velocity increases, which causes some deceleration. 4) Gravitational acceleration doesn’t change depending on the position or details of a

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: falling object on earth if there is no air resistance. With air resistance there is drag in relation to surface area and mass. Acceleration would be lower with a bigger object that has more area to be affected by air resistance. Conclusion: This experiment shows how to measure acceleration of a falling object, much more accurately than by hand. I can see firsthand how 9.8m/s^2 is the acceleration of gravity. Since the measurements weren’t done by hand the percent error is very low. d(mm) t^2 16mm ball 0.58 1.67 0.544 1.47 0.504 1.27 0.462 1.07 0.416 0.97 Distanc e (mm) Time (s) d(mm) t^2 19mm ball 0.58 1.67 0.544 1.47 0.504 1.27 0.46 1.07 0.415 0.97 Distanc e (mm) Time (s)...
View Full Document

{[ snackBarMessage ]}

### Page1 / 2

Experiment 2 Lab - falling object on earth if there is no...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online