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xperiment 11

xperiment 11 - equals pressure times distance times volume...

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Introduction: The net thermal work done to lift an object vertically is equal to the mechanical work done. To find the net work done of a cycle by a thermal engine, a P-V diagram would be needed, and the area of the parallelogram. To find the thermodynamic work done analytically us the formula: change in pressure times change in volume. Also translated as pi times distance squared over 4 times change in pressure at certain points times the change in height. Mechanical work would be calculated by the usual mass times gravity times height, and both of these results would be the same in the same testing. Analysis: 1. 10950.4 2. 10780 3. Thermal work/ mechanical work = 1.0158 Questions and Exercises: 1. The isobaric process for an ideal gas is when the pressure stays constant in a thermodynamic process and as the heat transfers it changes the internal energy of the system. Here work equals pressure times the change in volume 2. The adiabatic process for an ideal gas is when the net heat transfer equals zero. Work
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Unformatted text preview: equals pressure times distance times volume in the area of the process. 3. Heat does change from each point, but only slightly from B C and D A. 4. Yes, there is work done in each process but the net work of the whole process is close to zero A C is positive and from C A is negative. 5. The total heat added goes to zero and the net work is zero so the change in internal energy is zero in the complete cycle. Conclusion: In the experiment the thermodynamic work done does turn out to be equal to the mechanical work done. We found the work done with the different formulas and the ratio is close enough to one. This was the work done from the different heights but the net work of the whole process is zero because it returns to the original position. Also, the change in internal energy of the complete cycle is zero, because the heat leaves by the end of the process. So both the internal energy and work done is zero for the complete cycle....
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