crystaql violet lab - Tables and Graphs: Table 1: Crystal...

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Tables and Graphs: Table 1: Crystal Violet Absorbance Versus Time NaOH=0.0250M Trial 1 Time (min.) % Transmittance (%T) A = -log(%T/100) In A 1/ A 1 68.2 0.166 -1.79 6.02 2 72.6 0.139 -1.97 7.19 3 76.8 0.115 -2.17 8.72 4 80.2 0.0958 -2.35 10.4 5 83.6 0.0778 -2.55 12.9 6 86.2 0.0645 -2.74 15.5 7 88.2 0.0545 -2.91 18.3 8 90.2 0.0448 -3.11 22.3 9 91.6 0.0381 -3.27 26.2 10 92.8 0.0325 -3.43 30.8 11 94.0 0.0269 -3.62 37.2 12 94.8 0.0232 -3.76 43.1 13 95.4 0.0205 -3.89 48.9 14 95.8 0.0186 -3.98 53.7 15 96.0 0.0177 -4.03 56.4 Figure 1 Figure 2 Figure 3 Table 2: Crystal Violet Absorbance Versus Time NaOH=0.0250M Trial 2 Time (min.) % Transmittance (%T) A = -log(%T/100) In A 1/ A 1 61.4 0.212 -1.55 4.72 2 66.8 0.175 -1.74 5.71 3 71.0 0.149 -1.91 6.72 4 74.6 0.127 -2.06 7.86
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5 77.8 0.109 -2.22 9.17 6 81.0 0.0915 -2.39 10.9 7 83.6 0.0778 -2.55 12.9 8 85.4 0.0685 -2.68 14.6 9 87.4 0.0585 -2.84 17.1 10 89.2 0.0496 -3.00 20.1 11 91.0 0.0410 -3.20 24.4 12 93.6 0.0287 -3.55 34.8 13 95.0 0.0223 -3.80 44.9 14 96.0 0.0177 -4.03 56.4 15 96.0 0.0177 -4.03 56.4 Figure 4 Figure 5 Figure 6 Table 3: Crystal Violet Absorbance Versus Time NaOH=0.0500M Trial 1 Time (min.) % Transmittance (%T) A = -log(%T/100) In A 1/ A 1 70.2 0.154 -1.87 6.51 2 77.2 0.112 -2.19 8.90 3 82.6 0.0830 -2.49 12.0 4 86.4 0.0635 -2.76 15.8 5 89.0 0.0506 -2.98 19.8 6 91.0 0.0410 -3.20 24.4 7 92.2 0.0353 -3.34 28.4 8 92.8 0.0325 -3.43 30.8 9 92.8 0.0325 -3.43 30.8 10 93.0 0.0315 -3.46 31.7 11 93.6 0.0287 -3.55 34.8 12 94.0 0.0269 -3.62 37.2 13 94.6 0.0241 -3.73 41.5
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14 95.6 0.0195 -3.94 51.2 15 96.0 0.0177 -4.03 56.4 Figure Figure Figure Table 4: Crystal Violet Absorbance Versus Time NaOH=0.0500M Trial 2 Time (min.) % Transmittance (%T) A = -log(%T/100) In A 1/ A 1 69.2 0.160 -1.83 6.25 2 76.4 0.117 -2.15 8.55 3 83.0 0.0809 -2.51 12.36 4 87.6 0.0575 -2.86 17.39 5 91.0 0.0410 -3.20 24.41 6 93.4 0.0297 -3.52 33.72 7 94.8 0.0232 -3.76 43.12 8 96.2 0.0168 -4.08 59.44 9 96.6 0.0150 -4.20 66.57 10 97.2 0.0123 -4.40 81.08 11 96.8 0.0141 -4.26 70.80 12 96.8 0.0141 -4.26 70.80 13 96.6 0.0150 -4.20 66.57 14 96.4 0.0159 -4.14 62.80 15 96.2 0.0168 -4.08 59.44 Figure Figure Figure Calculations: A = -log for trial 1: 0.0500M NaOH, refer to table 1 -log (70.2/100) = 0.154
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The equation used was the simplified one. The –k would make the corresponding slopes + log [1.04] = y log [0.5] = 0.0177 = y [-0.301] y= -0.0589 (rounded to zero) K’ = k [OH - ] y -0.1676 = k [0.025] 0 k = -0.1676 x=1 x + y = 1 + 0 = 1 complete reaction order Conclusion: This experiment was performed to determine the rate law for the reaction of crystal violet with hydroxide ions in aqueous solution. The rate of a chemical reaction describes how fast a reaction
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This note was uploaded on 02/02/2012 for the course CHEMISTRY 212 taught by Professor Ha during the Spring '11 term at George Mason.

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crystaql violet lab - Tables and Graphs: Table 1: Crystal...

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