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Unformatted text preview: magnitues ) as r = r 1 + r 2 , we can write the moment of inertia in terms of the reduced mass as follows: I = m 1 r 2 1 + m 2 r 2 2 = r 2 where the reduced mass is deFned as: = m 1 m 2 m 1 + m 2 1 Thus, the kinetic energy in terms of the reduced mass becomes: KE = 1 2 r 2 2 = 1 2 v 2 The last equation shows us that in terms of the reduce mass, the dynamics of a rigid, diatomic rotor is equivalent to that of a particle of reduced mass (eFectively, we have reduced a two-body problem to a one-body problem). 2...
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