quizsolnS10 - Quiz Solutions: S10 (Section 011, CHEM444)...

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Unformatted text preview: Quiz Solutions: S10 (Section 011, CHEM444) 27th February 2010 1 Quiz 1 1.1 Problem 1 What is the ratio of the following values for a particle of Argon and Krypton at 298K? • ν Ar ave ν Kr ave ν Ar ave ν Kr ave = r m Kr m Ar = r 83 . 798 39 . 948 = 1 . 45 • ν Ar most probable ν Kr most probable ν Ar most probable ν Kr most probable = r m Kr m Ar • ν Ar rms ν Kr rms ν Ar rms ν Kr rms = r m Kr m Ar 1 1.2 Problem 2 What is the ratio of average kinetic energy of the two systems of Problem 1? < KE > Ar < KE > Kr = 1 We will show this the long way. < KE > Ar = Z ∞ 4 π m Ar 2 π k B T 3 / 2 1 2 m Ar ν 2 e (- m Ar ν 2 / 2 k B T ) ν 2 dν = 1 2 m Ar ν 2 rms = 1 2 m Ar 3 k B T m Ar = 3 2 k B T < KE > Kr = Z ∞ 4 π m Kr 2 π k B T 3 / 2 1 2 m Kr ν 2 e (- m Kr ν 2 / 2 k B T ) ν 2 dν = 1 2 m Kr ν 2 rms = 1 2 m Kr 3 k B T m Kr = 3 2 k B T Thus the ratio is 1 . For ideal gases, energy is a function of temperature....
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This note was uploaded on 02/02/2012 for the course CHEM 444 taught by Professor Dybowski,c during the Fall '08 term at University of Delaware.

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quizsolnS10 - Quiz Solutions: S10 (Section 011, CHEM444)...

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