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Frontiers and Controversies in Astrophysics: Lecture 13 Transcript
March 1, 2007
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Professor Charles Bailyn:
Last time, I wrote down the Schwarzschild metric, which was the sort of
culmination of the theoretical part of theof this section of the course. And I realized, as I was talking to
some of you afterwards about some of the implications of this, that the way Ione of the ways in which I
wrote it down might have been a little confusing. So, let me write it down again and I'll say a couple things.
And what I'm going to do is I'm going to write it down with a little
r
instead of a capital
R
and I'll tell you
why in just a minute. Obviously, it doesn't matter. I've just changed the notation slightly. And the reason I
want to do this is because I want to emphasize that this
r
, the little
r
, what I've now written down as a little
r
in this equation, is not the radius of the object;
r
is just a coordinate. It can be anything. It's not the radius of
the object for which the mass is giving you the Schwarzschild radius. The Schwarzschild radius is a very
specific radius.
r
s
= 2
GM
/
c
2
so that's a specific number. The little
r,
here, is just a coordinate and so is Ï† and Î¸, which
combine into this thing which I've called Omega [Î©] and
T
.
And so if you have an object of mass
M
and radiusI'll giveI'll call that
R
0
just to make sure that you
understand that this is the radius of the object. The radius of the object doesn't come into this metric. The
mass does, because the mass turns into the Schwarzschild radius and that's part of the equation. But the radius
of the object doesn't matter.
And so, if you then ask, well, what is a black hole? A black hole is something in which the radius of the
object is less than the Schwarzschild radius. Because if that's true, then there is some coordinate
r
, some little
r
where little
r
=
R
S
. And then, if you go up into these equations here verythese very strange things happen
when little
r
is equal to
R
S
. Yes, question?
Student:
Yesterday, the big group had [Inaudible]
Professor Charles Bailyn:
Oh you're right, you're right, it has to be the other way around, I'm sorry.
Student:
[Inaudible]
Professor Charles Bailyn:
This has to be squared. You're right on both counts, good.
R
S
/
r
. Yes, it better be
that way because
R
S
/
r
in the normal part of space is less than 1. So, thank you very much, sorry about that.
Okay, I think we're all right. Are we all right? Yeah, good.
Okay, so there is some
r
where
r
is equal to
R
S
, and then these very bizarre things start to happen. If
R
0
, the
radius of the actual object, is bigger than its Schwarzschild radius, then that isn't true. There's no
r
where
r
is
equal to
R
S
then no
r
equal to
R
S
. Now, you might think that somewhere inside the object, there would be a
little
r
, which is equal to the Schwarzschild radius. But that isn'tthat turns out not to be right either, because
the relevant
M
, the relevant mass
Student:
Can you lower the top slide?
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 Spring '06
 CharlesBailyn

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