Unformatted text preview: We know that the plane will have an equation of the form a ( x & 5) + b ( y & 0) + c ( z & 0) = 0 or ax + by + cz = 5 a . Since the point Y (0 ; & 3 ; 0) must be in this plane, we must have & 3 b = 5 a . Since the point Z (0 ; ; 8) must be in this plane, we must have 8 c = 5 a . Thus b = & 5 3 a and c = 5 8 a . If we choose a = 24 , we obtain b = & 40 and c = 15 : We thus obtain the same solution as given in Solution 1. 1...
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 Fall '10
 Ellermeyer
 Vectors

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