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Unformatted text preview: ) = x + y . Thus Z C F & d r = Z C r f & d r = f (1 ; 1) f (0 ; 0) = 2 0 = 2 . Now we show how to do the integral using the denition of line integrals: The curve C can be parameterized as r ( t ) = t i + t j t 1 from which we see that r ( t ) = i + j and F ( r ( t )) & r ( t ) = ( i + j ) & ( i + j ) = 2 . Thus Z C F & d r = Z C F ( r ( t )) & r ( t ) dt = Z 1 2 dt = 2 . 1...
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This note was uploaded on 02/05/2012 for the course MATH 2203 taught by Professor Ellermeyer during the Fall '10 term at FIU.
 Fall '10
 Ellermeyer
 Math

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