{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

hw01_solutions

# hw01_solutions - AA311 Atmospheric Flight Mechanics Autumn...

This preview shows pages 1–5. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: AA311 - Atmospheric Flight Mechanics Autumn 2010 University of Washington Homework 1 Solutions Problem 1 Not applicable. AA311 - Atmospheric Flight Mechanics Christopher Lum Printed by Mathematica for Students Problem 2 Using the equation of state r = p R T = 1.2 atm 1.01325 ä 10 5 N m 2 1 atm K 287 J kg K O H 300 K L ρ = 1.2 ∗ 1.01325 ∗ 10 5 287 ∗ 300 1.4122 The specific volume is simply v = 1 ê r v = 1 ê ρ 0.708117 So we have r = 1.4122 kg m 3 v = 0.708117 m 3 kg Clear @ v, ρ D 2 hw01_solutions.nb Printed by Mathematica for Students Problem 3 Part a. We can first convert temperature to Rankine T R = T F + 459.67 H convert fromFarenheit to Rankine L T = 85 + 459.67 544.67 Using the equation of state r = p R T = J 2116 lbf ft 2 N K 1716 ft lbf slug R O H 544.67 R L ρ = 2116 1716 ∗ T 0.00226394 So the density is r = 0.00226394 slug ë ft 3 We can easily compute the volume. V = H 10 m L H 5 m L H 3 m L … 3.281 ft m » 3 V = 10 ∗ 5 ∗ 3 ∗ H 3.281 L 3 5297.98 So the volume is V = 5297.98 ft 3 So the total mass is m = r V m = ρ V 11.9943 The weight of this in lbf is given by W = m a = 11.9943 slugs * 32.2 ft s 2 hw01_solutions.nb 3 AA311 - Atmospheric Flight Mechanics Christopher Lum Printed by Mathematica for Students W = m ∗ 32.2 386.216 So we have m = 11.9943 slugs W = 386.216 lbf Part b....
View Full Document

{[ snackBarMessage ]}

### Page1 / 12

hw01_solutions - AA311 Atmospheric Flight Mechanics Autumn...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online