Homework 6 - AOE 3104 Homework #6 Solutions Problem 1. A...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: AOE 3104 Homework #6 Solutions Problem 1. A constant-power aircraft has the following parameter values: S = 1000 ft 2 , T , SL = 15 , 000 lb , P shaft , SL = 5000 hp , p = 0 . 8 C D L = 0 . 04 + 0 . 08 C 2 L C L max , L = 3 . 2 L = 0 . 25 W L = 45 , 000 lb (The subscript L denotes landing configuration.) Given that the aircraft lands at 1.2 V stall , compute the ISA sea-level landing distance in feet assuming that spoilers are deployed ( C L 0) and thrust is zeroed at the instant of touchdown. Repeat the previous analysis, assuming that the aircraft lands in a 25 mph headwind. Solution. Part A) The stall speed in landing configuration is V stall , L = radicalBigg 2 W L SL SC L max , L = radicalBigg 2(45 , 000 lb) (2 . 377 10 3 sl / ft 3 )(1000 ft 2 )(3 . 2) = 108 . 8 ft / s so the touchdown speed is V TD = 1 . 2 V stall , L = 130 . 5 ft / s . The landing acceleration is V = A- BV 2 where A =- L g =- (0 . 25)(32 . 2 ft / s 2 ) =- 8 . 05 ft / s 2 and B = g W parenleftbigg 1 2 SC D parenrightbigg = 32 . 2 ft / s 2 45 , 000 lb parenleftbigg 1 2 (2 . 377 10 3 sl / ft 3 )(1000 ft 2 )0 . 04 parenrightbigg = 3 . 40 10 5 ft 1 The landing distance is s = 1 2 B ln parenleftbigg 1- B A V 2 TD parenrightbigg = 1022 ft ....
View Full Document

Page1 / 5

Homework 6 - AOE 3104 Homework #6 Solutions Problem 1. A...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online