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Unformatted text preview: If we do the same extraction using three 20 mL portions of CH 2 Cl 2 we would have, x/20 mL (0.600 x)/100 mL = 8.4 x = 0.3761 grams of caffeine in first extraction, 0.2239 grams left x/20 mL (0.2239 x)/100 mL = 8.4 x = 0.1403 grams of caffeine in second extraction, 0.08356 grams left x/20 mL (0.08356 x)/100 mL = 8.4 x = 0.0430 grams of caffeine in third extraction, 0.04053 grams left. So, after three 20 mL CH 2 Cl 2 extractions 0.3761 g + 0.1403 g + 0.0403 g = 0.5567 grams of caffeine would have been extracted as compared to 0.500 grams of caffeine extracted using a single 60 mL sample of CH 2 Cl 2 . Therefore, about 11% more caffeine is extracted using three 20 mL portions of CH 2 Cl 2 than a single 60 mL sample....
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 Spring '11
 gelfand
 Chemistry

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