prob.viii-4 - Eh: PROBLEM 8-4 SOLUTION Tcmfirature Fi0lds...

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Unformatted text preview: Eh: PROBLEM 8-4 SOLUTION Tcmfirature Fi0lds In Fresh And Erradialed Fuel Bianchan'a’s porosity 00n‘00ti0n l—P 1+(a-|}P km For 33% Ehmrflfical density P = I- i Pm.- i-0_12 : 1 km 1+[15— 0012 1““ f 1' 1~0_05 km _ 1+{15— H005 km {2} Frum Equations [1) and [2] 1—012 1+ 15 4:10.05 [(0.33 = ' ' IE ' ——‘—"— = . 5? I+[lj*— IJDJE 1_{}_fl5 km D 39 R095 F01" uncracked case, 0ng =0.005? k “= 1? 5'! Rev Duncan II}. 15"}? Page [01" 5 pages = 0.395? {2.7"} = 2.413 Whn K Fnr the cracked case, k3,?“ = 1135mm“ 9.135 = {1.3957 (2.4} = 2J5 me K 1] Calcuiatc Tclanu 31116 Tum: q ink“ R Tci = Tuc- T TELth E Till + A. Uncmxkcd Case: kc = 1? WIan q“ = 44 kWHm h:°=43flfl me K Kw =- 5.26 mm = 6.25 x ID'3m 3.. = 0.36 mm =U.Efi :«:1I[II’3 m 6,; a 9.23 mm = 0.23 x [0’3 .11 TN = 295. “c m... =11.”- 3. - 5!. = 5.25 x m-1 — 0.3.5.1104 - 0.23 x If!" = 5.17:: Wm Page 1 n1" 5 pages F'mblcm 51-4 Solution [4} {5) Pmblem EH. Sulutiml ;°=2_413 wrm I: From Equations {3 j}, {4) and [5} Luna" 1 {mama-3 + 0.351134 2:: - n “ 6.25xln'* '13: 295 + 44x14:l 2:: -5.17x10‘” 43m) d4x1U'3 4:: ~14}?! Tum]: 2 ‘- ‘—“ 1119.1] "C *Nute; [l' we use difffircnt R5, instead R3 = R“, R +13%... R9: Jig—“25.235xm'3m 443m} = "' + __.—-.— TI“ “‘55'9 2:.5235310-3-43043 =w4_1 “C 44311)" = +——-+-— Tm“ 654'} dirt-1.415 —' 2] 11.2 “C B. Cracked Case: h 3 =3 100:) Wm R 1:92.15 WJmK Page: 3 ul' 5 pach Problem ‘54 Seiutien 44x131 5.353: I e-3 + 13363:] e ‘3 Err- n 6.26xlfl‘3 J = 355.9"C 44x10] 35F 5.]?!10—5 +3 lflfl'fl Tf..= 355.9 + = 399.6 “C 443L113?“ Tm” = 399.6 + 43: -2.15 = 21323.2 ‘13 I. *Nere: If we use different RE, instead RE = Rm 44x13! 2:: +523511fl'3 r 316D!) Tru= 355.3 + = 39313 “C =1—43c‘1fl'3 3' = 393.3 + m 4:: -3.15 = 11321.2 °C 2. Volume Weighted Average Temperature . "r- q r L”! Timer-er _L [Tm +m[1"R§u}]r-dr Tm: = R e r- 3m‘ - [it RE: TI! = Tfe + emf A. Uneraeked Case: 44x11? '1'hr = 6TH? + _ EEQAIE Page 4 of 5 rages . thltm 1M Sfll'LLliUfl = 1394.9 °C J5. Cracked C1151: 44x10?” Efl-EJS 'l'“ = 399.5 + =1213.‘:J'°C ' Nuts. 11" we use difl'erunt RE, instead R8 = Rm R n + Ra .- __'-|. Rg=LJ—2——-T5.233xifl m 6641 Mxlfll T“ ' fizz-2.413 41333.2“: 936 44xm'3 Il'=-| + T" J ' Err-2J5 — 1219.9“C Page 5 of 5 pagm ...
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This note was uploaded on 02/02/2012 for the course PHY 4049 taught by Professor Acosta during the Fall '08 term at University of Florida.

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prob.viii-4 - Eh: PROBLEM 8-4 SOLUTION Tcmfirature Fi0lds...

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