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# prob.x-5 - ‘1"= 2 ﬁxlﬂs Btumr ft3=-haat ﬂux at...

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Unformatted text preview: ‘1"= 2 ﬁxlﬂs Btumr ft3= -haat ﬂux at the clad surface Th1: Sﬂﬂ F= coolant inlet Tamperam 1i: i mass ﬂaw rate in the channel unﬂlﬂ Energy Equation- cpx'n Ez—T = q“ - a: . D, and Tim} = the Heat Balance Equmzinn+ J1 {TW {2} — T {3}] = q" _ f I! l' l' -. wax] JFH- “P “Tm cum {I} 1} far water as [Numki = 0523 RED-3 . 131-13333 .__ 111323 Prﬂ'ﬂ'a K pmolﬂﬁ u )ﬂﬁ’ﬂ = £11123 {E}? :n: [ﬁfﬁ x {TE'IP'SI when: A a chnmf ﬂow area. [1333 = 431123 U.231><1.21') x L_n._G33L__"-"-3x{mJD-E 0.325 o.231x1.ﬂ92x[n-3] = 1.243 rhﬂ'g RM Novamber'i'. 199-5 Page I of 3 pagas Problem I'D—5 Solution = '2 ‘ 11 E = -3 ~ _4i_ _ .- [A P 4 11 1.119315 113.15: "P“, _%_ﬁ_ﬂ333 ft] (2) 7.1:; 1...: ‘1} = [-515 Pm - 1-043 = 1.325 x 34% - 1545 21.2925 5* _ ._:. Nu = “151.191:1.2925{1.245}{m}”3 = 1.5 1551113 __ 1;}: .MBNu numhﬂl‘ is deﬁned by N1] = hug; [harm DE = DH}, :1; E? '1"? . , . ‘3 IE. ‘9" .11. D: 11513 x 33333 1155"“? (Blufft hr ”F} :3!" :45. -'_'mnximum clad Surfacc Immature occurs at 2 = L = 12 ﬂ, and 1111's put TwiL} = EMF and 3:15 iiéfur Ii]. —':f: u— .5111 ' 13.55 ><{:'u] 3 Cum _ -_ I1" 41.: 451"T£DL_ 'ij [Twin ijm 13.55"] ' up “0 m ' 1155151111551 ' Cp{Tw-{L:I'T-—1n} 25me mg; _ 2.55.105 5: II: x 11.45112 x12 _ g 15.55 x 11111 1255111111 _ '. I115 ﬁlﬁiﬁuc using He :15 cut-lam, we can cumpute h, using Frcsscr's cnmlaﬁnn [E1]. lﬂ-lﬂﬂh} and .;D1Ftus-Euelter cu naiaﬂon. Page 2 {If 3 [155:5 Emblem 111-5 Sululiun. :4 _ . 13.4 _ P13 Y” WI}: ”-3 -.. {Numh— 13.1333 RED 3 P1- - 11.1133 [—kE [T .4 = 11.1133 (Lt—:31] lﬁ" ”'3 (111)0-3 1:14 ' 111332111243 11 . - 11.113311111133133 = 3.3133 3: {1319-3 f 11 = 11.3213 +31% 1333 - 11.113 11-? [Pm — 1} (1.113;: 11111 51.3) = 11.3213 + 11.1433 11 1.339 - 11.113 1-3111113 = 1.11343 . Nu : 1.11343 32.31311111110-5 _1' 1-1 2; = 9.133 . ”7 . .3: . . .11 1311 N11 11.11333 x1 11343 11 3.3113 111111)” 111.333 1: [1111” _u1 11 111111 Eq. {1} 11.1111 1 = 1. and T“, {L} = 31.11131 3 +11 1:11 1 13.533AmF-3 11,111 : '. [i1 q {11110'1-— E] TEDL - :0 113.533 1cm. 1131—1111 011wa {Ll-T11} 5 5 111- 3311113 1111 2_2.5x1ﬂ m: [11.13113113: E 111533 X 1011'] 1.243 34130 TF1“ IL} ' Tin = :11 - 2331.31.11}:L1 - 33113.1 = 11 I " d1 = 33311 1111111111- Pagc 3 of 3 pages ...
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prob.x-5 - ‘1"= 2 ﬁxlﬂs Btumr ft3=-haat ﬂux at...

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