This preview shows page 1. Sign up to view the full content.
Unformatted text preview: v j 2 = ( u v ) & ( u v ) by property 4 = ( u + ( v )) & ( u + ( v )) by denition of u v = ( u + ( v )) & u + ( u + ( v )) & ( v ) by property 3 = u & ( u + ( v )) + ( v ) & ( u + ( v )) by property 1 = u & u + u & ( v ) + ( v ) & u + ( v ) & ( v ) by property 3 = u & u u & v v & u + v & v by property 2 = u & u u & v u & v + v & v by property 1 = j u j 2 2 u & v + j v j 2 by property 4. This completes the proof. 1...
View
Full
Document
This note was uploaded on 02/05/2012 for the course MATH 2203 taught by Professor Ellermeyer during the Fall '10 term at FIU.
 Fall '10
 Ellermeyer
 Vectors, Scalar, Dot Product

Click to edit the document details