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Unformatted text preview: Physics 253a 1 Problem Set 4 Solutions October 7, 2010 1. (a) The tree level diagram has a single vertex ig Recall that the LSZ formula amputates the external legs, so we just have i M = ig . It turns out this process is actually kinematically disallowed. Imagine boosting to the initial particles rest frame. In this frame its clear that theres no way for a particle of mass m to decay to two particles of mass m , since that would violate conservation of energy. Mathematically, this fact comes in when we add back the momentum conserving delta function 4 ( p 1 p 2 p 3 ), which simply vanishes when all three momenta are on shell. For now, where just interested in playing around with Feynman rules, so we neednt worry. (b) More than one graph is possible here, but well find out later that only one of them contributes to the scattering amplitude (again, its related to the LSZ formula): p 1 k + p 1 p 2 k + p 3 p 3 k Here k is an undetermined momentum that runs around the loop. Note that momentum is conserved at the upperright vertex because p 1 p 2 = p 3 . Once again, LSZ says we can ignore the external legs, so the Feynman rules give i M = Z d 4 k (2 ) 4 ( ig ) 3 i k 2 m 2 i ( k + p 1 ) 2 m 2 i ( k + p 3 ) 2 m 2 Note that the symmetry factor is 1. Physics 253a 2 (c) Lets label our graph like this x 1 x 3 x 2 y 1 y 2 y 3 This graph stands for the set of Wick contractions of h  T ( x 1 ) ( x 2 ) ( x 3 ) 1 3! ig 3! Z d 4 y 1 ( y 1 ) 3 ig 3!...
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This note was uploaded on 02/04/2012 for the course PHYS 253A at Harvard.
 '10
 SCHWARTZ
 Physics

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