University Physics with Modern Physics with Mastering Physics (11th Edition)

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3.16 : a) Solving Eq. (3.18) with m 75 . 0 , 0 0 = = y y gives s 391 . 0 = t . b) Assuming a horizontal tabletop, 0 0 = y v , and from Eq. (3.16), s m 58 . 3 / ) ( 0 0 = - = t x x v x . c) On striking the floor, s m 83 . 3 2 0 - = - = - = gy gt v y , and so the ball has a velocity of magnitude s m 24 . 5 , directed
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Unformatted text preview: ° 9 . 46 below the horizontal. d) Although not asked for in the problem, this y vs. x graph shows the trajectory of the tennis ball as viewed from the side....
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  • Trajectory of a projectile, 0.75 m, 3.83 m, horizontal tabletop, 3.58 m, 5.24 m

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