HW1 Solution - AA 310 HW#1 Solution Problem 1 (6pts) Given:...

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1 AA 310 HW#1 Solution Problem 1 (6pts) Given: !"#$ = 1 . 524 ࠵± !"#$%&’ = 5 . 203 ࠵± !"#$%& = 9 . 519 ࠵± !"#$ ! = 1 ࠵± !"#$ ! = 1 ࠵±²³ Assume: Circular orbit !"#$%& = 2 ! !"#$%& ! !" !"# ࠵± !"# = ࠵±²³´µ²´ !"#$%& !"#$ ! = 2 !"#$%& ! ࠵± !"# 2 !"#$ ! ! ࠵± !"# = !"#$%& ! !"#$ ! ! !"#$%& = !"#$ ! !"#$%& ! !"#$ ! ! !"#$ = 1 ࠵± 1 . 524 ࠵± ! 1 ࠵± ! = 1 . 881 ࠵± !"#$%&’ = 11 . 868 ࠵± !"#$%& = 29 . 369 ࠵± Tabulated values: !"#$ = 1 . 881 ࠵± !"#$%&’ = 11 . 869 ࠵± !"#$%& = 29 . 696 ࠵±
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