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ECE201_05_R_combo_V_I_div

# ECE201_05_R_combo_V_I_div - ECE 201 Lecture 5 Resistor...

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ECE 201 Lecture 5 Resistor combinations; voltage & current division

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Revisit KCL + - Circuit element -2cos(2t) A -9cos(2t) A 3cos(2t) A cos(2t) A ? Current in: -2cos(2t) A Current out: [-9cos(2t)]+cos(2t)+ ? +3cos(2t) Apply KCL: -2cos(2t)= [-9cos(2t)]+cos(2t)+ ? +3cos(2t) Rearrange: ? = [-2cos(2t)]-[-9cos(2t)]-cos(2t)-3cos(2t) + - Circuit element 2cos(2t) A 9cos(2t) A 3cos(2t) A cos(2t) A ? Current in: 9cos(2t) A Current out: cos(2t)+ ? +3cos(2t)+2cos(2t) Apply KCL: 9cos(2t)= cos(2t)+ ? +3cos(2t)+2cos(2t) ? = 9cos(2t)-cos(2t)-3cos(2t)-2cos(2t)
Revisit KVL Find V AB , V BC and V AC A B C E F G H - + 1V + - 3V + - 6V - + + - 2V 10V Set V A =0 V V E =1 V V F =-2 V V H =-8 V V C =-18 V V B =3 V V AB =V A -V B =-3V; V BC =V B -V C =21V; V AC =V A -V C =18V

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Example: Find v 1 , v 2 , v 3 , and v 4 Problem 2.7
Problem 2.6: find V x

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Find I out and V out
Example: Find power absorbed or delivered to the two sources and three resistors 4 nodes, 6 branches and 6 elements + - 6 A 5 + - V x + - V y i x i y A B D C R 1 60 V 10 A -2 A R 2 i z 5

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Apply KCL and KVL KCL, node A: i x =-4 A + - 6 A 5 + - V x + - V y i x i y A B D C R 1 60 V 10 A -2 A R 2 i z 5 KCL, node C: i z =+12 A KCL, node C: i y =+8 A KVL, ACBA: V x =-20V V AC = 40 V KVL, BCDB: V y = 50 V
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