sol99f2

Hence the pid compensator is given by d s 2 14065s s

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 2+ = 1:4065s s 2s + 10 2 The actual step response for DGs 20 = ssK 0:2s + 1 ; + 8s + 3 K = 2:8131 is given by with MATLAB which satis es both requirements: Step Response From: U(1) 1.4 1.2 1 Amplitude 0.8 To: Y(1) 0.6 0.4 0.2 0 0 0.5 1 1.5 2 2.5 3 Time (sec.) 3. Denote D1 s and D2 s as the PID compensators designed in Prob.1 and Prob. 2 respectively. i By G0 = 40=240 = 1=6, we have lim D Gs = lim 10:0623 G0 = lim 1:6771 s!0 1 lim lim 14:065 lim 2:3442 s!0 D2 Gs = s!0 s G0 = s!0 s using the expressions for D1 s in 1 and D2 s in 2. Because sensitivity performance requires DGs to be large,...
View Full Document

This note was uploaded on 02/03/2012 for the course EE 3530 taught by Professor Chen during the Fall '07 term at LSU.

Ask a homework question - tutors are online