This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Chapter 5 The RootLocus Design Method C ( s ) P ( s ) 6 r e u y Closedloop poles: 1 + P ( s ) C ( s ) = 0 . Denote L ( s ) := P ( s ) C ( s ) L ( s ) = K ( s z 1 )( s z 2 ) ··· ( s z m ) ( s p 1 )( s p 2 ) ··· ( s p n ) where z 1 , . . . , z m are the openloop zeros, p 1 , . . . , p n are the open loop poles, and K is a variable gain. Objective: study how the closedloop poles change when K varies from 0 to ∞ . 1 Find all points satisfying L ( s ) = 1 . magnitude condition :  L ( s )  = 1 phase condition : 6 L ( s ) = (2 k + 1)180 o , k = 0 , ± 1 , . . . • Magnitude condition can always be satisfied by a suitable K ≥ 0. • Phase condition does not depend on the value of K (but does depend on the sign of K ): 6 L ( s ) = m X i =1 6 ( s z i ) n X j =1 6 ( s p j ) = (2 k + 1)180 o . Thus the key is to find all those points that satisfy the phase condition. 2 Example : Consider L ( s ) = K ( s z 1 )( s z 2 ) ( s p 1 )( s p 2 )( s p 3 ) , p 2 = p 1 . • a pole is represented by a “ × ” • a zero is represented by a “ ◦ ”. The phase of L ( s ) at a point s in the complex plane is 6 L ( s ) = 6 ( s z 1 ) + 6 ( s z 2 ) 6 ( s p 1 ) 6 ( s p 2 ) 6 ( s p 3 ) = φ 1 + φ 2 α 1 α 2 α 3 . 6 * × ” O y × × 9 Y K M z 2 z 1 p 3 p 1 p 2 s α 1 α 2 φ 1 α 3 φ 2 σ jω 3 Root Locus Rules: 0 ≤ K ≤ ∞ 1 . The root locus is symmetric with respect to the real axis. 2 . The root loci start from n poles p i (when K = 0) and approach the n zeros ( m finite zeros z i and n m infinite zeros when K → ∞ ). 3 . The root locus includes all points on the real axis to the left of an odd number of open loop real poles and zeros. 4 . As K → ∞ , n m branches of the root locus approach asymp totically to n m straight lines (called asymptotes) with angles θ = (2 k + 1)180 o n m , k = 0 , ± 1 , ± 2 , . . . and the starting point of all asymptotes is on the real axis at σ = n X i =1 p i m X j =1 z j n m = X poles X zeros n m . 5. The breakaway points (where the root loci meet and split away, usually on real axis) and the breakin points (where the root loci meet and enter the real axis) are among the roots of the equation: dL ( s ) ds = 0. (On real axis only those roots satisfy Rule 3 are breakaway or breakin points.) 4 6. The departure angle φ k (from a pole, p k ) is given by φ k = m X i =1 6 ( p k z i ) n X j =1 ,j 6 = k 6 ( p k p j ) ± 180 o . (In the case p k is l repeated poles, the departure angle becomes φ k /‘ .) The arrival angle ψ k (at a zero, z k ) is given by ψ k = m X i =1 ,i 6 = k 6 ( z k z i ) + n X j =1 6 ( z k p j ) ± 180 o . (In the case z k is l repeated zeros, the arrival angle becomes ψ k /‘ .) 5 Example : Asymptotes and breakaway points are illustrated. Con sider an open loop transfer function L ( s ) = K s ( s + 4)( s + 5) ....
View
Full
Document
This note was uploaded on 02/03/2012 for the course EE 3530 taught by Professor Chen during the Fall '07 term at LSU.
 Fall '07
 Chen

Click to edit the document details