PS4_Solution[2]

# PS4_Solution[2] - \ Name: \Wxﬁé/Xé Section: J EE331...

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Unformatted text preview: \ Name: \Wxﬁé/Xé Section: J EE331 Homework PS4 — spring 2011 Problems from Alexander & Sadiku: CH5 0 5.8 — Warm up! Ans: a) -5V, b) 4V 0 5.13 (Remember your ideal Op Amp assumptions, equations 5.5 and 5.7) — A voltage divider works quite nicely to get this problem rolling. 5.21 5.27 5.37 5.47 Additional Problems (Instructor Option): 0 Read page 196-197 in your text and solve Practice Problem 5.12 (on page 197) 0 Any as assigned by instructor Page 1 of 1 Chapter 5, Problem 8 Obtain v0 for each of the op amp circuits in Fig. 5.47. ‘N 10kg; '1\/ u“ 1 mA a) \ASz SMMMN ‘ (35) K5?) Chapter 5, Problem 13 Find v0 and i0 in the circuit of Fig. 5.52. Figure 5.52 for Prob. 5.13 a use \LHW Dwmwﬂv \fA VA: lV- qokn :<0-‘l'\/i (Tomi-Hem} Chapter 5, Problem 21. Calculate V0 in the op amp circuit of Fig. 5.60. 10 k9 Figure 5.60 For Prob. 5.21. 3VAI.V ‘2 0.5 mA ( Hm. \ l I N" \/—_ 1V~ O-SMA'lom = W 2%? Chapter 5, Problem 27. Chapter 5, Problem 37 Determine the output of the summing ampliﬁer in Fig. 5.74. I ‘ n/ r- "‘ " 0‘ mm A \ \/ \ ‘ A \ | a I): 2“ :OAMA .__. "TOT‘llhlh 9mm 0 } 2 ’3“ :~0.\MA 35 BOY—IL IToY W V: 0V~ owls-32m: Chapter 5, Problem 47. The circuit in Fig. 5.79 is for a difference ampliﬁer. Firid V0 given that v1 =1V and V2 = 2V. Figure 5.79 For Prob. 5.47. 6 \/A: ;\/~ 90m 2 lm\/ ()Knmxm 0 I. : IV’ Lg)": __ [HO/“A I _/ QVJ'L o \/0: [,g;\/ + ‘hOMA-‘sowk [ti-WI V C Hg." (Jada?) DAC is sh(1w;iilﬁ}‘:ing.‘53'v7. ermine IV,,| for [V.V2V3] = [0101. D ‘ V2V3] 7': Wot = 1.25 v is desired. what should be [v.vzvm I? get IV"! = 1.75 V. what should be [VszngW tom 3. E :, S vs owmwwv Figure 5.31 Three-bit DAC; for Practice Prob. 5.12. ~ 9‘? ’r R4 + 35%] (5&3) -‘/o- ’R-‘V. “EV: 35 3 ‘1 33:31 W ’rO '1 0-S\/ a) N0! ao‘dl mm mm _ 2/" ’r-——— JVW‘LSV ‘0) NO‘ IoLo\ 90m K ‘01 a) to! —=> NJ“- ‘13014 +0 + :6“ ~. 1.;5\/ 12“ ‘2‘.“ (0L ~ . 0‘) [H .33 N0\- ‘0L\+ 90v.\ +—Ll~o\c\~ NV ouTWTUVDI) \/ 000 0 oo 1 0-35 ol 0 0.5 o\ | 0-?5 \ o O l J70 | o\ 1.38 l \ O [-5 ® SMMM48/I%ML¢W\ ( ‘ \ 1.?5 Loo\(_(A— AMA\03‘¥O~D%|‘\'L’Q 2 dc. .__mI 00:55 :02me woom © 29.300 35 250 35383 wEEoqum: Emmi E:me / E.sz _ o _ wo.«:< SR o _ _ 32\$ oEEam _ _ _ €53 88 “5-359 EEEQE< 22322 03. a: E B 222 5 25w? @225 EEWCO dc. .=mI 8:55 :09me woom © EmEEoo a Btu gamma—3:0 U<Q 80053:335552853232 S cc 5% cc :8me ...
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## This note was uploaded on 02/03/2012 for the course ELECTRICAL EE331 taught by Professor Rudd during the Fall '11 term at Naval Academy.

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PS4_Solution[2] - \ Name: \Wxﬁé/Xé Section: J EE331...

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