CondProb - (4.4 Conditional Probability From Cross Tabs we...

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(4.4) Conditional Probability: From Cross Tabs we know: P(A|B) read “Probability of A given B” = ° ?∩?± ° ?± Example : In a certain population: The probability a person lives to be 80 is 75% The probability a person lives to be 90 is 63% Find the probability that an 80 year old will live to be 90. Example : You and your roommate have 9 frozen pizzas: 4 veggie and 5 meat lovers. You randomly select a pizza out of the freezer and have it for dinner tonight and tomorrow your roommate goes to the store and gets 3 more pizzas of whichever kind you ate today. P(eat Veggie pizza today) = P(eat Veggie Pizza tomorrow | ate Veggie Pizza today) = P(eat Meat Lovers tomorrow | ate Veggie Pizza today) =
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P(eat Veggie Pizza today and tomorrow) = P(Meat lovers pizza today and tomorrow) = P(eat veggie pizza tomorrow) = P(eat same kind of Pizza both days) = Multiplication Rule: ° ? ∩ ?± = ° ?±° ?²?± = ° ?±° ( ? | ? ) For 3 events: ° ? ∩ ? ∩ ?± = ° ?±° ?²?±° ( ? | ? ∩ ? ) In this example: P(eat Veggie pizza next 3 days) =
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(4.4) Independence **Deck of cards breakdown: 52 total, 26 red and 26 black, of the red we have 13 hearts,
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CondProb - (4.4 Conditional Probability From Cross Tabs we...

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