CondProb

# CondProb - (4.4 Conditional Probability From Cross Tabs we...

This preview shows pages 1–4. Sign up to view the full content.

(4.4) Conditional Probability: From Cross Tabs we know: P(A|B) read “Probability of A given B” = ° ?∩?± ° ?± Example : In a certain population: The probability a person lives to be 80 is 75% The probability a person lives to be 90 is 63% Find the probability that an 80 year old will live to be 90. Example : You and your roommate have 9 frozen pizzas: 4 veggie and 5 meat lovers. You randomly select a pizza out of the freezer and have it for dinner tonight and tomorrow your roommate goes to the store and gets 3 more pizzas of whichever kind you ate today. P(eat Veggie pizza today) = P(eat Veggie Pizza tomorrow | ate Veggie Pizza today) = P(eat Meat Lovers tomorrow | ate Veggie Pizza today) =

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
P(eat Veggie Pizza today and tomorrow) = P(Meat lovers pizza today and tomorrow) = P(eat veggie pizza tomorrow) = P(eat same kind of Pizza both days) = Multiplication Rule: ° ? ∩ ?± = ° ?±° ?²?± = ° ?±° ( ? | ? ) For 3 events: ° ? ∩ ? ∩ ?± = ° ?±° ?²?±° ( ? | ? ∩ ? ) In this example: P(eat Veggie pizza next 3 days) =
(4.4) Independence **Deck of cards breakdown: 52 total, 26 red and 26 black, of the red we have 13 hearts,

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 7

CondProb - (4.4 Conditional Probability From Cross Tabs we...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online