Ch16 - Q15.1a Here is a rod lying on the y axis. It is...

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Q15.1a Here is a rod lying on the y axis. It is uniformly charged positive. What is the direction of the net electric field at location A? A
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Q15.1b We have set up an integral to find the electric field of a uniformly charged rod, of length L and charge Q , at a location on the midline. What are the limits of integration? 1) 0 to 2) −∞ to + 3) L to + L 4) L /2 to + L /2 5) 0 to L
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Q15.1c A uniformly charged rod is 2.5 m long. Its charge is –2e-7 coulombs. The observation location is 4 cm from the rod, along the midline. + = 2 2 2 0 4 1 L r r Q E πε What is r ? 1) 2.5 2) –2e-7 3) 0.04 4) 4 5) 1.25
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Q15.1d A rod with charge 2e-8 C is 50 cm long, and lies on the x-axis. We need to calculate E a distance of 1 cm from the midpoint of the rod. Which formula should we use? 1) Exact 2) Approximate 3) Either exact or approximate 4) Neither – we must do it numerically 5) Neither – we need to integrate
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Q15.1e A thin rod 2 m long with charge –2e-7 C, lies on the x-axis, centered at the origin. What is the electric field due to the
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This note was uploaded on 02/04/2012 for the course PHY 303L taught by Professor Turner during the Spring '08 term at University of Texas at Austin.

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Ch16 - Q15.1a Here is a rod lying on the y axis. It is...

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