# Ch22 - E 5 E 4 E 2 E 3 E 1 Q21.4a A large positive charge...

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Q21.1a, b, c, d What is inside the box? 1) Net positive charge 2) Net negative charge 3) Net charge of zero 4) Not enough information given

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Q21.2a E = 600 V/m, r=3 cm, θ = 25 degrees What is the electric flux on this disk- shaped surface? 1. 600 V· m 2. 544 V· m 3. 253 V· m 4. 1.70 V· m 5. 1.54 V· m 6. 0.717 V· m
Q21.2b 800 V/m What is the net electric flux on the box? 1. 0 V· m 2. 0.36 V· m 3. 0.84 V· m 4. 8.04 V· m 5. 8.52 V· m

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Q21.3a 800 V/m What is the net charge inside the box? 1) 3.2 E –12 C 2) 7.6 E –12 C 3) –3.2 E –12 C 4) –7.6 E – 12 C 4) 1.3 E –11 C 6) –1.3 E –11 C
Q21.3b If E 1 = E 2 = E 3 = E 4 = 826 N/C and E 5 = 600 N/C, what is the magnitude and sign of the charge enclosed in the box? 1) -1.42e-11 C 2) 1.05e-11 C 3) -3.9e-12 C 4) 1.42e-11 C 5) 2.56e-12 C 3 cm 3 cm 3 cm 3.5 cm 3 cm 6 cm 3 cm

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Unformatted text preview: E 5 E 4 E 2 E 3 E 1 Q21.4a A large positive charge is outside an empty, neutral metal box. Measurements show that the electric field inside the box is zero. Why is this electric field zero? 1) The box polarizes and contributes a field inside the box that exactly cancels the field of the positive charge. 2) Because metals contain mobile electrons, the electric field of the positive charge is blocked from getting into the box. 3) The box acquires a net negative charge which neutralizes the field of the positive charge. Q21.6a R = 3 cm, B = 1e-5 T What is I? 1.) 0 A 2.) 1.9e-1 A 3.) 1.9e-6 A 4.) 1.5 A 5.) 19 A Q21.6b = 30, B1 = 2e-4 T, B2 = 1e-4 T Width = 0.5 m, Height = 0.2 m What is l d B v v ? 1.) 0 T m 2.) 8.7e-5 T m 3.) 1.7e-4 T m 4.) 2.0e-4 T m 5.) 2.1e-4 T m...
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## This note was uploaded on 02/04/2012 for the course PHY 303L taught by Professor Turner during the Spring '08 term at University of Texas at Austin.

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Ch22 - E 5 E 4 E 2 E 3 E 1 Q21.4a A large positive charge...

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