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Yeast mating - Results section (1)

Yeast mating - Results section (1) - cells will be white We...

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Results: Figure 1: Genotypes alpha 1 R alpha 2 r a 1 R RR Rr a 2 r Rr rr Here we have the yeast mating table showing the crossing of these haploid strains of yeast. We mated alpha1 (which is represented by dominant allele “R”) and alpha2 (which is represented by recessive allele “r”) with a1 and a2. The haploid strain a1 is also represented by “R”, and the strain a2 is represented by the allele “r”. When crossed, the resulting genotypes are homozygous “RR”, heterozygous “Rr”, and homozygous “rr”, with a respective 1:2:1 genotypic ratio. Figure 2: Predicted Phenotypes alpha 1 R alpha 2 r a 1 R White White a 2 r White Red From the background information in the lab packet, we know that “R” is the dominant allele for white colored yeast cells, and “r” is the recessive allele, resulting in red cells. So when our haploid crosses result in a diploid homozygous genotype of “RR” we predict that the resulting
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Unformatted text preview: cells will be white. We also predicted that the diploid homozygous genotype rr would result in red cells. The background information in the packet also states that the diploid heterozygote is white, so we predicted that the diploid genotype Rr would also result in white cells. Based on this, we predicted a phenotypic ratio of 3:1 (3 white for every 1 red). Figure 3: Observed Phenotypes alpha 1 R alpha 2 r a 1 R White White a 2 r White Red Our observed phenotypes matched what we predicted. The homozygous genotype rr did result in red cells, which makes sense. Both of the genotypes RR and Rr resulted in white cells. This means that the gene for white cells is completely dominant over the gene for red cells. The observed phenotypic ratio was 3:1 just like we predicted....
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