Unformatted text preview: teams we get the same game), so the total number of diļ¬erent games is 1 2 Ā· 10! 4!4!2! = 1575 . Answer: there are 10! 4!4!2!2! diļ¬erent games. 2. The sample space is { AB,AC,BC } . We have P ( { AB,AC } ) = P ( AB ) + P ( AC ) = 5 8 , P ( { AB,BC } ) = P ( AB ) + P ( BC ) = 5 8 and P ( AB ) + P ( AC ) + P ( BC ) =1 . Therefore, P ( { AC,BC } ) = P ( AC ) + P ( BC ) =2 Ā³ P ( AB ) + P ( AC ) + P ( BC ) Ā“Ā³ P ( AB ) + P ( AC ) Ā“Ā³ P ( AB ) + P ( BC ) Ā“ =25 85 8 = 3 4 . Answer: The probability that one of the chosen courses is Communications is 3 / 4. 1...
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 Winter '12
 AlexanderBarvinok
 Probability, Probability theory, The ATeam, Committee, ways

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