{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# ps01 - Statistics 403 Problem Set 1 Due in lab on Friday...

This preview shows pages 1–2. Sign up to view the full content.

Statistics 403 Problem Set 1 Due in lab on Friday, September 17th 1. Suppose we have the following probability distribution: x P ( X = x ) 1 0.19 2 0.09 3 0.07 4 0.15 5 0.21 6 0.03 7 0.01 8 0.03 9 0.12 10 0.10 (a) What is the probability that X is odd? Solution: The probability that X is odd is 0 . 19 + 0 . 07 + 0 . 21 + 0 . 01 + 0 . 12 = 0 . 6 . (b) What is the probability that X is evenly divisible by 3? Solution: X is evenly divisible by 3 only if X equals 3, 6, or 9. Thus the probability is 0 . 07 + 0 . 03 + 0 . 12 = 0 . 22 . (c) Are these two events independent? Why or why not? Solution: If the events are independent, the probabilities must satisfy the mul- tiplication rule. The value of X is both odd and evenly divisible by 3 only if X equals 3 or 9. This probability is 0 . 07+0 . 12 = 0 . 19, which is substantially greater than the product 0 . 6 × 0 . 22 (where 0 . 22 is the probability that X is divisible by 3). Thus these two events are not independent (they are positively dependent). (d) Construct the cumulative probability distribution for this random variable.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern