{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# exam1W09sol - Name-Section/Time of lecture-Professor/GSI...

This preview shows pages 1–8. Sign up to view the full content.

Name: -------------------------------- Section/Time of lecture: -------------------------------- Professor/GSI: ______________ _ MATH 216 WINTER 2009 MIDTERM I To get full score you need to carefully explain what you did. No calculators allowed. 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
I Problem I Points I Score I 1 10 2 28 3 22 4 26 2 I TOTAL I 88 2
Problem 1. I a-4 pt I Verify that the function y ( x) = x 2 sin x satisfies y" - y' + y = 3x cos x. X 2 ' y 5M1 X \j ~ 2x~~-r Y:~X !I 2_ ~ _ 2 ~·'I )( -+- 2 X. Go::l X -t 2 X W s X:- 'f. 5 j Y\.)<, 3

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
I b-6pt I Sketch the slope field and solution curves for ~~ = x + y 2 . Include enough detail to be able to give a rough sketch of the solution curves with y(l) = 0 and y(O) = 0.5. y ·---~-- -1.5 -0.5 4 ·······/ / 0.5 1.5 X
Problem 2. la-8ptl Find the (explicit or implicit) solution for xdy- - 2 - = O,y(l) = n. dx cosy . J~ rL I ]i - ZM:J u_~ Jj ::: yt-- s;/ - 2~r--r C 0 O+C 5

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
I b-lOpt I Solve xy' + 2 _ 1 y x2 = 0, y(l) = 1. ql-+ b. - \ J x )" - x> / j -e .cc: 2 _Llt< '~ /)j y L \..._ ..::::: >( ( '1.2_.)1 '/ = ·~ xY _,&,x+ C I O+ c "-) - J 6 X
I c-10pt I Let x(t) represent the number of grams of salt dissolved in a water solution. Assume that x(t) satisfies x' = x- x 2 and x = 0.1 when t = 0 minute. How many minutes will it take for an additional 0.1 grams of salt to dissolve?

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern